Spieth has 71 at Australian Open, trails early leader by 5
ABS-CBN Sports on Nov 26, 2015 11:18 AM
Jordan Spieth, right, of the U.S. chats with Geoff Ogilvy of Australia as they walk along the 8th fairway during the Australia Open Golf Tournament in Sydney, Australia, Thursday, Nov. 26, 2015. (AP Photo/Rob Griffith)
AP Sports Writer
SYDNEY (AP) — Jordan Spieth birdied his opening hole and bogeyed his last during an even-par 71 Thursday that saw the defending champion trail early leader Lincoln Tighe by five strokes on a blustery, hot day at the Australian Open.
In temperatures of 35 degrees Celsius (95 Fahrenheit), Spieth started on the 10th hole with a birdie, bogeyed a par-3 on each nine and finished with a 5 on the par-4 ninth at The Australian Golf Club.
Australia's Tighe was the early clubhouse leader with a 66.
Geoff Ogilvy, the 2010 champion who was playing in the same group as Spieth, was two strokes behind after a 68.
The third member of that group, 1997 winner Lee Westwood, shot 70, as did U.S. Amateur and 2015 NCAA champion Bryson DeChambeau.